factorx(x+5)(x-4)=x^3

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Solution for factorx(x+5)(x-4)=x^3 equation: 


Simplifying
factorx(x + 5)(x + -4) = x3

Reorder the terms:
acfortx(5 + x)(x + -4) = x3

Reorder the terms:
acfortx(5 + x)(-4 + x) = x3

Multiply (5 + x) * (-4 + x)
acfortx(5(-4 + x) + x(-4 + x)) = x3
acfortx((-4 * 5 + x * 5) + x(-4 + x)) = x3
acfortx((-20 + 5x) + x(-4 + x)) = x3
acfortx(-20 + 5x + (-4 * x + x * x)) = x3
acfortx(-20 + 5x + (-4x + x2)) = x3

Combine like terms: 5x + -4x = 1x
acfortx(-20 + 1x + x2) = x3
(-20 * acfortx + 1x * acfortx + x2 * acfortx) = x3
(-20acfortx + 1acfortx2 + acfortx3) = x3

Solving
-20acfortx + 1acfortx2 + acfortx3 = x3

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Combine like terms: x3 + -1x3 = 0
-20acfortx + 1acfortx2 + acfortx3 + -1x3 = 0

Factor out the Greatest Common Factor (GCF), 'x'.
x(-20acfort + acfortx + acfortx2 + -1x2) = 0


Subproblem 1
Set the factor 'x' equal to zero and attempt to solve:

Simplifying
x = 0

Solving
x = 0

Move all terms containing a to the left, all other terms to the right.

Add '-1x' to each side of the equation.
x + -1x = 0 + -1x
Remove the zero:
0 = -1x

Simplifying
0 = -1x

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

Subproblem 2
Set the factor '(-20acfort + acfortx + acfortx2 + -1x2)' equal to zero and attempt to solve:

Simplifying
-20acfort + acfortx + acfortx2 + -1x2 = 0

Solving
-20acfort + acfortx + acfortx2 + -1x2 = 0

Move all terms containing a to the left, all other terms to the right.

Add 'x2' to each side of the equation.
-20acfort + acfortx + acfortx2 + -1x2 + x2 = 0 + x2

Combine like terms: -1x2 + x2 = 0
-20acfort + acfortx + acfortx2 + 0 = 0 + x2
-20acfort + acfortx + acfortx2 = 0 + x2
Remove the zero:
-20acfort + acfortx + acfortx2 = x2

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

The solution to this equation could not be determined.

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